A lady lives on a island 1km from land she paddles her canoe at 3km/h and jogs at 5km/h the nearest store is? - canoe paddles
3 Km along the coast from the tip of the island on the coast closest to other similar actions aligned. where he worked on land to get at the pharmacy to a minimum?
Saturday, January 9, 2010
Canoe Paddles A Lady Lives On A Island 1km From Land She Paddles Her Canoe At 3km/h And Jogs At 5km/h The Nearest Store Is?
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Hello,
ReplyDeleteLet x = distance from the coast, where the lady of the country should have their canoes. Then the rest of the trip would be the remaining 3 - x km.
If paddling diagonal of the island on a triangle with legs of 1 km x km away from the dock the boat √ (1 + x ²).
Distance
------------- = Time
Rate
So that the distance Canoe / Boat trot jogging distance / speed = time + travel
This is the equation:
Y1 = √ (1 + x ²) / 3 + (3 - x) / 5
When it entered into the computer, finds its minimum. This occurs when x = .75 y = 867
So, if you his boat along the coast of 75 km and ran the rest of 2.25 kilometers, would need a total of 867 hours.
Hope this helps! :-)
It takes 20 minutes to 1 km and 12 min Line 1-km run
ReplyDeletea total of 56 minutes to the right
So, if angles to run his boat in an area, 1 km from the Bank needs to his 40 minutes on the platform and another 12 minutes
As min at 52nd instead of 56 minutes if it directly
Duane Anderson
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That is the point x km from the coast of the island closest to you.
ReplyDeleteAnswer: 0.6 kilometers from the top of the nearest coast of the island served as a framework.
With the principle of light refraction, that light always travels to reach the destination in the shortest possible time,
sin i / sin r = 5 / 3
=> [X / √ (1 + x ^ 2)] / sin 90 ° = 3 / 5
= 5 x = 3 √ (1 + x ^ 2)
=> 25x ^ 2 = 9 (1 + x ^ 2)
=> 16x ^ 2 = 9
=> X = 3 / 5 = 0.6 kilometers
Canadians ask you now, ask questions!
ReplyDeleteSuppose the Earth at a distance x from the nearest point on the island, paddling distance sqrt (x ^ 2 +1) (Pythagoras) and ran the track is 3-x.
ReplyDeleteSun Time = distance / speed = sqrt (x ^ 2 +1) / 3 + (3-x) / 5
We need to find the smallest value, and differentiate, so that is equal to 0.
So x / (3 * sqrt (x ^ 2 +1)) -1 / 5 = 0
Add 1 / 5 of each side and location of the lot:
x ^ 2 / x ^ 2 +1 = 9 / 25
..... Algebra over
x ^ 2 = 9 x ^ 2 / 25 + 9 / 25
16x ^ 2 / 25 = 9 / 25
16x ^ 2 = 9
x ^ 2 = 9 / 16
So x = 3 / 4
You should land 3 / 4 of a km from the nearest point on the coast of the island.
The amount of distance canoe sqrt (x ^ 2 +1)
ReplyDeleteThe distance is 3-x
The total time for a visit to the shop
T = sqrt (x ^ 2 +1) / 3 + (3-x) / 5
Now the derivative equal to 0 and solve for X.
1 / 3 (sqrt (x ^ 2 +1)) - 1 / 5 = 0
to land x = 4 / 3 km along the beach.
Plug in your equation of time T and total loan.